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Help with Combinatorics Math Question, Please
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[QUOTE="zachvac, post: 1170375, member: 26306"] 7-high as in no straights, pairs, or flushes? Just look at the number of combos: For 7 high: 4 combos (2-3-4-5-7, 2-3-4-6-7, 2-3-5-6-7, 2-4-5-6-7) In each combo each of the 5 can be any suit so 4*4^5 Then we have to take out flushes, 4 for each combo, so 4*4^5 - 4*4 = 4080 I just did this right now so I could have missed something, but I think that's right. The other ones are tougher, biggest thing is just finding how many combos there can be for like K high without making a straight. Or maybe you could just find total combos and subtract out straights like I did with flushes. [/QUOTE]
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