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Message: [QUOTE="zachvac, post: 1170433, member: 26306"] ok let's say for A-high since it should be toughest. First can be one of 52 cards. Next can be one of 48, 44, 40, 36. Multiply those together, than we have to remove straights and flushes. We can remove the straight to 5/6/7/8/9/T/J/Q/K/A so 10*4^5 combos. Flushes there can be 13 choose 5 combos times 4 = 4*(13!/(5!*8!)) Then we have to add back in the straight flushes because we double counted them but that's only 4*10 = 40 Let's try this method for 7 high. 24*20*16*12*8 - 2*4^5 - 4*(6!/5!) + 4*2 = 735,216 = I did something wrong lol. Even if we divide initial product by 5 so order doesn't matter we're still way way way too big. wtf did I do wrong? edit: found it should divide by 5! because there are that many ways to arrange 5 numbers duh. That comes up with the right answer of 4080. [/QUOTE]