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[QUOTE="PokerPete, post: 487603, member: 15622"]
Hmmmm ok let's see EXACTLY how that is calculated:
 
there are FOUR different Royal Flushes available (one for each suit of course)
 
so your odds for the first card are:
 
any of the 20 10 through ace of any suit out of a deck of 52
 
So for card 1 the "Probability" of getting one of these 20 is 20/52 (say we are dealt the 10 of diamonds)
 
Once the first is dealt, now the remainer MUST be the same suit (diamonds), so the cards remaining are reduced to AKQJ of diamonds out of the 51 remaining cards:
 
so card 2 "Probability": 4/51 (say we get the A diamonds next)
 
the next card MUST be either Kd Qd or Jd out of the 50 remaining:
 
so card 3 "Probability": 3/50 (Say we get the Kd next leaving Q & J diamonds missing)
 
so card 2 "Probability": 2/49
 
and card 5 "Probability": 1/48
 
To find the "Probability" for this "Combination" occurring, we multiply all the "Probabilities" together
 
or
 
20*4*3*2*1 / 52*51*50*49*48 = 480/31187520 :eek: 
 
now divide top and bottom by 480 and get the magic:
 
1 / 649740 "Probability"
 
so thats the "Probability" of any five cards dealt from a deck of 52 cards being a "royal flush"....
 
Now you're talking about a ring of ten players each getting two cards then sharing 5 community cards...my "sadistics" & probability is a little rusty, but it's my gut "truthiness" :rolleyes: feeling that what you're applying here doesn't fit the way the game is played... and the first most obvious difference is the fact that you have 7 cards to make your Royal instead of just 5...and nine OTHER players are sharing 5 of those cards....
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