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Message: [QUOTE="WarEagle1266, post: 1218016, member: 57302"] Had to delete my previous post to post this, because apparently I can only post 7 messages a day as a new member; wish I knew that before I wrote my long reply and then lost it all. Here's the short version: Not sure about your 2nd calculations, but I found a different way of looking at it. If one player deals out 2 face down cards and 3 for the flop, the odds that he will have a pocket pair and make a set in the same hand is (16*11.76) to 1, which is 188.16 to 1. So, if 9 players are playing, it is 3 times as likely that this situation will happen for just one player, or (188.16/9) to 1, which is 20.9 to 1. So, the chances of 3 players having a pocket pair and making a set on the flop would increase the odds by the third order, being (20.9^3) to 1, which is 9138.1 to 1 odds. This seems like the most simple solution to me, which usually means it's right. What do you think James? [/QUOTE]